REINFORCED CONCRETE WALL ADEQUACY CHECK

Design according to HK CoP 2013
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1.0 INPUT DATA

1.1 Material Properties

fcu = MPa   Characteristic concrete cube strength

fy = MPa   Characteristic steel yield strength

Es = MPa   Steel modulus of elasticity

γc =   Partial safety factor for concrete (Cl 6.1.2.4)

γs =   Partial safety factor for steel (Cl 6.1.2.4)

1.2 Wall Geometry

cc = mm   Concrete cover

Lw = mm   Wall length

tw = mm   Wall thickness

Hu = mm   Unsupported height

Frame Type:
Top Condition:
Bottom Condition:

Figure 1: Wall Section

RC Wall Section

1.3 Reinforcement Details

φv = mm   Vertical bar diameter

sv = mm   Vertical bar spacing

Layers =   Number of reinforcement layers

Horizontal Reinforcement

φh = mm   Horizontal bar diameter

sh = mm   Horizontal bar spacing

1.4 Applied Loads (ULS)

NEd = kN   Design axial force

Mu2x = kNm   In-plane moment (larger end moment)

Mu1y = kNm   Out-of-plane moment (smaller end moment)

Mu2y = kNm   Out-of-plane moment (larger end moment)

2.0 CALCULATIONS

2.1 Geometry Check

Effective length factor (Table 6.13)

k = 0.80   (Based on end conditions)
He = k × Hu
He = 0.80×5825 = 4660.00 mm

Wall classification

Lw/tw = 1200/250 = 4.80
Is Wall: YES   (Lw/tw > 4 per Cl 1.4.4)

2.2 Slenderness Check (Cl 6.2.2)

Slenderness ratio

λ = He/tw
λ = 4660/250 = 18.64
λlimit = 45 (Table 6.15)
Check λ: PASS   (λ = 18.64 ≤ 45)

Short vs Slender Check (Cl 6.2.2.3)

Wall Type: SLENDER   (λ = 18.64 > 15)

2.3 Minimum Reinforcement (Cl 9.6)

Concrete area

Ac = Lw × tw
Ac = 1200×250 = 300000 mm²

Provided reinforcement

As,per m = (Layers×π×φv²/4)×(1000/sv)
As,per m = 2×π×20²/4×(1000/125) = 502.65 mm²/m
As,total = As,per m × (Lw/1000)
As,total = 502.65×1.2 = 603.19 mm²

Reinforcement ratio

ρ = As,total × 100/(Lw × tw)
ρ = 603.19×100/(1200×250) = 0.201 %
Min Reinforcement Check: PASS   (ρ = 0.201% > 0.40% and ≤ 4.0%)

2.4 Second-Order and Minimum Moments

Additional moment factor (Cl 6.2.1.4)

βa = (1/2000) × λ²
βa = (1/2000)×18.64² = 0.174

Curvature correction factor K (Cl 6.2.1.4.2)

K = min(1.0; (1.2 − NEd×1000/(Ac×fcu))/0.7)
K = min(1.0; 1.2-1742×1000/(300000×45)/0.7) = 1.00

Additional moment

Ma = (NEd × tw × βa × K)/1000
Ma = 1742×250×0.174×1.00/1000 = 75.83 kNm

Minimum eccentricity (Cl 6.2.1.2)

emin,y = max(0.05×tw; 20)
emin,y = max(0.05×250; 20) = 20.00 mm
emin,x = max(0.05×Lw; 20)
emin,x = max(0.05×1200; 20) = 60.00 mm
My,min = NEd × emin,y/1000
My,min = 1742×20/1000 = 34.84 kNm
Mx,min = NEd × emin,x/1000
Mx,min = 1742×60/1000 = 104.52 kNm

Combined out-of-plane moment

Miy = max(0.4×Mu2y; 0.4×Mu1y + 0.6×Mu2y)
Miy = max(0.4×0.50; 0.4×0.35+0.6×0.50) = 0.44 kNm

Total design moments

Mtotal,y = max(Mu2y; Miy+Ma; Mu1y+Ma/2; My,min)
Mtotal,y = 76.27 kNm
Mtotal,x = max(Mu2x; Mx,min)
Mtotal,x = 448.00 kNm

2.5 Capacity Analysis - Biaxial Interaction

Idealization of Wall into 4-Bar Column for Design

Steel geometry

d2 = cc + φh + φv/2
d2 = 35+10+20/2 = 55.00 mm
d = twd2
d = 250-55 = 195.00 mm
εcu = 0.0035

Design stresses

fy,d = fy/γs
fy,d = 500/1.15 = 434.78 MPa
fcu,d = 0.67×fcu/γc
fcu,d = 0.67×45/1.5 = 20.10 MPa

2.6 Out-of-Plane Capacity (MRd,y)

Neutral axis position (solved from equilibrium)

xy = 87.50 mm   (Limited per Cl 6.1.2.4)

Force components

Fcy = fcu,d×Lw×min(0.9×xy; tw)/1000
Fcy = 1974.38 kN
Fs1y = (As,total/2 × min(max(εcu × (xy - d2) / xy × Es; -fy,d); fy,d)) / 1000
Fs1y = 920.24 kN
Fs2y = (As,total/2 × min(max(εcu × (xy - d) / xy × Es; -fy,d); fy,d)) / 1000
Fs2y = -1311.27 kN

Out-of-plane moment capacity

MRd,y = (Fcy×(tw/2 − 0.45×xy) + Fs1y×(tw/2 − d2) + Fs2y×(tw/2 − d))/1000
MRd,y = 76.27 kNm

2.7 In-Plane Capacity (MRd,x)

Neutral axis position (solved from equilibrium)

xx = 343.75 mm   (Limited per Cl 6.1.2.4)

Force components

Fcx = fcu,d×tw×min(0.9×xx; Lw)/1000
Fcx = 1742.70 kN
Fs1x = (As,total/2 × min(max(εcu × (xx - d2) / xx × Es; -fy,d); fy,d)) / 1000
Fs1x = 1311.27 kN
Fs2x = (As,total/2 × min(max(εcu × (xx - (Lw - d2)) / xx × Es; -fy,d); fy,d)) / 1000
Fs2x = -1311.27 kN

In-plane moment capacity

MRd,x = (Fcx×(Lw/2 − 0.45×xx) + Fs1x×(Lw/2 − d2) + Fs2x×(Lw/2 − (Lwd2)))/1000
MRd,x = 448.00 kNm

2.8 Biaxial Interaction Check

Balance point capacity

Nuz = (0.35×fcu×(AcAs,total) + 0.67×fy×As,total)/1000
Nuz = 0.35×45×(300000-603.19)+0.67×500×603.19/1000 = 6308.91 kN

Exponent αn

αn = min(2.0; max(1.0; 1.0 + (NEd/Nuz − 0.2)/0.6))
αn = min(2.0; max(1.0; 1.0+(1742/6308.91-0.2)/0.6)) = 1.00

Quick biaxial interaction check

(Mtotal,x/MRd,x)αn + (Mtotal,y/MRd,y)αn
= (448.00/2172.54)1.10 + (66.94/327.91)1.10 = 0.35
Biaxial Check: FAIL   (2.00 ≥ 1)

2.9 Biaxial Design per Clause 6.1.2.4

Interpolation factor β (Table 6.14)

Nratio = NEd×1000/(Ac×fcu)
Nratio = 1742×1000/(300000×45) = 0.129
β = max(min(−1.16×Nratio + 1; 1); 0.3)
β = max(min(-1.16×0.129+1; 1); 0.3) = 0.85

Effective dimensions

h' = min(0.75×Lw; Lwd2)
h' = min(0.75×1200; 1200-55) = 900.00 mm
b' = twd2
b' = 250-55 = 195.00 mm

Effective moment ratio check

Mtotal,x/h' = 448/900 = 0.498
Mtotal,y/b' = 76.27/195 = 0.391

Effective moment

Meff,x = Mtotal,x + β×(h'/b')   (X-axis dominates)
Meff,x = 448 + 0.85×(900/195) = 722.00 kNm

Utilization ratio

Utilization = Meff,x/MRd,x
Utilization = 722/448 = 1.61
Slender Wall Check: FAIL   (Utilization = 1.61 ≥ 1)

Figure 2: Idealization of Wall into 4-Bar Column

RC Wall 4-Bar Column

2.10 Axial Capacity Check (Cl 6.5.2)

Axial capacity

NRd = (0.35×fcu×(AcAs,total) + 0.67×fy×As,total)/1000
NRd = 0.35×45×(300000-603.19)+0.67×500×603.19/1000 = 6308.91 kN

Axial utilization

NEd/NRd = 1742/6308.91 = 0.276
Axial Capacity Check: PASS   (NEd = 1742.00 kN ≤ NRd = 6308.91 kN)

2.11 Horizontal Reinforcement Check (Cl 9.6.3)

Required horizontal reinforcement

Ash,min1 = 0.001×Ac
Ash,min1 = 0.001×300000 = 300.00 mm²
Ash,min2 = 0.25×As,total
Ash,min2 = 0.25×603.19 = 150.80 mm²
Ash,min = max(Ash,min1; Ash,min2)
Ash,min = max(300; 150.80) = 300.00 mm²

Provided horizontal reinforcement

Ash,prov = (Layers×π×φh²/4)×(He/sh)
Ash,prov = 2×π×10²/4×(4660/200) = 366.44 mm²
Horizontal Reinforcement: PASS   (Ash,prov = 366.44 mm² ≥ Ash,min = 300.00 mm²)

*** OUTPUT SUMMARY ***

Design Summary

Wall Classification: WALL

Slenderness Ratio, λ = 18.64 ≤ 45

Wall Type: SLENDER

Effective Height, He = 4660.00 mm

Total Reinforcement, As,total = 603.19 mm²

Reinforcement Ratio, ρ = 0.201 %

Min Reinforcement Check: PASS

Additional Moment, Ma = 75.83 kNm

In-Plane Capacity, MRd,x = 448.00 kNm

Out-of-Plane Capacity, MRd,y = 76.27 kNm

Biaxial Check: FAIL

Slender Wall Utilization: 1.61

Axial Capacity: PASS

Horizontal Reinforcement: PASS

RESULTS

DESIGN CHECK - INCREASE WALL CAPACITY OR REDUCE LOADS
NOTE: ALWAYS VERIFY BI-AXIAL RESULTS USING MORE ACCURATE TOOLS LIKE Oasys AdSec or spColumn