1.0 INPUT DATA
1.1 Material Properties
fcu = MPa Characteristic concrete cube strength
fy = MPa Characteristic steel yield strength
Es = MPa Steel modulus of elasticity
γc = Partial safety factor for concrete (Cl 6.1.2.4)
γs = Partial safety factor for steel (Cl 6.1.2.4)
1.2 Wall Geometry
cc = mm Concrete cover
Lw = mm Wall length
tw = mm Wall thickness
Hu = mm Unsupported height
Frame Type:
Top Condition:
Bottom Condition:
1.3 Reinforcement Details
φv = mm Vertical bar diameter
sv = mm Vertical bar spacing
Layers = Number of reinforcement layers
Horizontal Reinforcement
φh = mm Horizontal bar diameter
sh = mm Horizontal bar spacing
1.4 Applied Loads (ULS)
NEd = kN Design axial force
Mu2x = kNm In-plane moment (larger end moment)
Mu1y = kNm Out-of-plane moment (smaller end moment)
Mu2y = kNm Out-of-plane moment (larger end moment)
2.0 CALCULATIONS
2.1 Geometry Check
Effective length factor (Table 6.13)
k = 0.80
(Based on end conditions)
He = k × Hu
He = 0.80×5825 = 4660.00 mm
Wall classification
Lw/tw = 1200/250 = 4.80
Is Wall: YES
(Lw/tw > 4 per Cl 1.4.4)
2.2 Slenderness Check (Cl 6.2.2)
Slenderness ratio
λ = He/tw
λ = 4660/250 = 18.64
λlimit = 45 (Table 6.15)
Check λ: PASS
(λ = 18.64 ≤ 45)
Short vs Slender Check (Cl 6.2.2.3)
Wall Type: SLENDER
(λ = 18.64 > 15)
2.3 Minimum Reinforcement (Cl 9.6)
Concrete area
Ac = Lw × tw
Ac = 1200×250 = 300000 mm²
Provided reinforcement
As,per m =
(Layers×π×φv²/4)×(1000/sv)
As,per m = 2×π×20²/4×(1000/125) =
502.65 mm²/m
As,total = As,per m ×
(Lw/1000)
As,total = 502.65×1.2 = 603.19 mm²
Reinforcement ratio
ρ = As,total × 100/(Lw ×
tw)
ρ = 603.19×100/(1200×250) = 0.201 %
Min Reinforcement Check: PASS
(ρ = 0.201% > 0.40% and ≤ 4.0%)
2.4 Second-Order and Minimum Moments
Additional moment factor (Cl 6.2.1.4)
βa = (1/2000) × λ²
βa = (1/2000)×18.64² = 0.174
Curvature correction factor K (Cl 6.2.1.4.2)
K = min(1.0; (1.2 −
NEd×1000/(Ac×fcu))/0.7)
K = min(1.0; 1.2-1742×1000/(300000×45)/0.7) = 1.00
Additional moment
Ma = (NEd × tw ×
βa × K)/1000
Ma = 1742×250×0.174×1.00/1000 = 75.83 kNm
Minimum eccentricity (Cl 6.2.1.2)
emin,y = max(0.05×tw; 20)
emin,y = max(0.05×250; 20) = 20.00 mm
emin,x = max(0.05×Lw; 20)
emin,x = max(0.05×1200; 20) = 60.00 mm
My,min = NEd ×
emin,y/1000
My,min = 1742×20/1000 = 34.84 kNm
Mx,min = NEd ×
emin,x/1000
Mx,min = 1742×60/1000 = 104.52 kNm
Combined out-of-plane moment
Miy = max(0.4×Mu2y;
0.4×Mu1y + 0.6×Mu2y)
Miy = max(0.4×0.50; 0.4×0.35+0.6×0.50) = 0.44
kNm
Total design moments
Mtotal,y = max(Mu2y;
Miy+Ma;
Mu1y+Ma/2; My,min)
Mtotal,y = 76.27
kNm
Mtotal,x = max(Mu2x;
Mx,min)
Mtotal,x = 448.00
kNm
2.5 Capacity Analysis - Biaxial Interaction
Idealization of Wall into 4-Bar Column for Design
Steel geometry
d2 = cc + φh +
φv/2
d2 = 35+10+20/2 = 55.00 mm
d = tw − d2
d = 250-55 = 195.00 mm
εcu =
0.0035
Design stresses
fy,d = fy/γs
fy,d = 500/1.15 = 434.78 MPa
fcu,d =
0.67×fcu/γc
fcu,d = 0.67×45/1.5 = 20.10 MPa
2.6 Out-of-Plane Capacity (MRd,y)
Neutral axis position (solved from equilibrium)
xy = 87.50
mm
(Limited per Cl 6.1.2.4)
Force components
Fcy =
fcu,d×Lw×min(0.9×xy;
tw)/1000
Fcy = 1974.38
kN
Fs1y = (As,total/2 ×
min(max(εcu × (xy - d2) /
xy × Es; -fy,d);
fy,d)) / 1000
Fs1y = 920.24
kN
Fs2y = (As,total/2 ×
min(max(εcu × (xy - d) / xy ×
Es; -fy,d); fy,d)) / 1000
Fs2y = -1311.27
kN
Out-of-plane moment capacity
MRd,y = (Fcy×(tw/2 −
0.45×xy) + Fs1y×(tw/2 −
d2) + Fs2y×(tw/2 −
d))/1000
MRd,y = 76.27
kNm
2.7 In-Plane Capacity (MRd,x)
Neutral axis position (solved from equilibrium)
xx = 343.75
mm
(Limited per Cl 6.1.2.4)
Force components
Fcx =
fcu,d×tw×min(0.9×xx;
Lw)/1000
Fcx = 1742.70
kN
Fs1x = (As,total/2 ×
min(max(εcu × (xx - d2) /
xx × Es; -fy,d);
fy,d)) / 1000
Fs1x = 1311.27
kN
Fs2x = (As,total/2 ×
min(max(εcu × (xx - (Lw -
d2)) / xx × Es;
-fy,d); fy,d)) / 1000
Fs2x = -1311.27
kN
In-plane moment capacity
MRd,x = (Fcx×(Lw/2 −
0.45×xx) + Fs1x×(Lw/2 −
d2) + Fs2x×(Lw/2 −
(Lw − d2)))/1000
MRd,x = 448.00
kNm
2.8 Biaxial Interaction Check
Balance point capacity
Nuz = (0.35×fcu×(Ac −
As,total) +
0.67×fy×As,total)/1000
Nuz = 0.35×45×(300000-603.19)+0.67×500×603.19/1000 = 6308.91 kN
Exponent αn
αn = min(2.0; max(1.0; 1.0 +
(NEd/Nuz − 0.2)/0.6))
αn = min(2.0; max(1.0;
1.0+(1742/6308.91-0.2)/0.6)) = 1.00
Quick biaxial interaction check
(Mtotal,x/MRd,x)αn +
(Mtotal,y/MRd,y)αn
= (448.00/2172.54)1.10 + (66.94/327.91)1.10 =
0.35
Biaxial Check: FAIL
(2.00 ≥ 1)
2.9 Biaxial Design per Clause 6.1.2.4
Interpolation factor β (Table 6.14)
Nratio =
NEd×1000/(Ac×fcu)
Nratio = 1742×1000/(300000×45) = 0.129
β = max(min(−1.16×Nratio + 1; 1); 0.3)
β = max(min(-1.16×0.129+1; 1); 0.3) = 0.85
Effective dimensions
h' = min(0.75×Lw; Lw −
d2)
h' = min(0.75×1200; 1200-55) = 900.00 mm
b' = tw − d2
b' = 250-55 = 195.00 mm
Effective moment ratio check
Mtotal,x/h' = 448/900 =
0.498
Mtotal,y/b' = 76.27/195 =
0.391
Effective moment
Meff,x = Mtotal,x +
β×(h'/b')
(X-axis dominates)
Meff,x = 448 + 0.85×(900/195) =
722.00 kNm
Utilization ratio
Utilization = Meff,x/MRd,x
Utilization = 722/448 = 1.61
Slender Wall Check: FAIL
(Utilization = 1.61 ≥
1)
Figure 2: Idealization of Wall into 4-Bar Column
2.10 Axial Capacity Check (Cl 6.5.2)
Axial capacity
NRd = (0.35×fcu×(Ac −
As,total) +
0.67×fy×As,total)/1000
NRd = 0.35×45×(300000-603.19)+0.67×500×603.19/1000 = 6308.91 kN
Axial utilization
NEd/NRd = 1742/6308.91 = 0.276
Axial Capacity Check: PASS
(NEd = 1742.00 kN ≤
NRd = 6308.91 kN)
2.11 Horizontal Reinforcement Check (Cl 9.6.3)
Required horizontal reinforcement
Ash,min1 = 0.001×Ac
Ash,min1 = 0.001×300000 = 300.00 mm²
Ash,min2 = 0.25×As,total
Ash,min2 = 0.25×603.19 = 150.80 mm²
Ash,min = max(Ash,min1;
Ash,min2)
Ash,min = max(300; 150.80) = 300.00 mm²
Provided horizontal reinforcement
Ash,prov =
(Layers×π×φh²/4)×(He/sh)
Ash,prov = 2×π×10²/4×(4660/200) =
366.44 mm²
Horizontal Reinforcement: PASS
(Ash,prov = 366.44 mm² ≥
Ash,min = 300.00 mm²)
*** OUTPUT SUMMARY ***
Design Summary
Wall Classification: WALL
Slenderness Ratio, λ = 18.64 ≤
45
Wall Type: SLENDER
Effective Height, He = 4660.00
mm
Total Reinforcement, As,total = 603.19 mm²
Reinforcement Ratio, ρ = 0.201 %
Min Reinforcement Check: PASS
Additional Moment, Ma = 75.83
kNm
In-Plane Capacity, MRd,x = 448.00 kNm
Out-of-Plane Capacity, MRd,y = 76.27 kNm
Biaxial Check: FAIL
Slender Wall Utilization: 1.61
Axial Capacity: PASS
Horizontal Reinforcement: PASS
RESULTS
DESIGN CHECK - INCREASE WALL CAPACITY OR REDUCE LOADS
NOTE: ALWAYS VERIFY BI-AXIAL RESULTS USING MORE ACCURATE TOOLS LIKE Oasys AdSec or spColumn